C/C++语言实现扫雷(详解攻略)

学习目标:


扫雷GAME

与上篇一样,创建三个文件

test.c文件代码实现

#include "game.h"

void menu()
{
          
   
	printf("###################
");
	printf("######1. play######
");
	printf("######0. exit######
");
	printf("###################
");

}

void game()
{
          
   
	//扫雷游戏的实现
	char mine[ROWS][COLS] = {
          
    0 };
	//show数组是用来存放排查出雷的信息
	char show[ROWS][COLS] = {
          
    0 };

	//初始化棋盘
	init_board(mine, ROWS, COLS,0);
	init_board(show, ROWS, COLS,*);
	//打印棋盘
	//show_board(mine, ROW, COL);
	show_board(show, ROW, COL);
	//布置雷
	set_mine(mine, ROW, COL);
	//show_board(show, ROW, COL);
	//排查雷
	find_mine(mine, show, ROW, COL);
}
void test()
{
          
   
	int input = 0;
	srand((unsigned int)time(NULL));

	do
	{
          
   	
		menu();
		printf("请选择:>
");
		scanf("%d", &input);
		switch (input)
		{
          
   
		case 1:
			game();
			break;
		case 0:
			printf("退出游戏
");
			break;
		default:
			printf("选择错误,请重新选择:>
");
		}
	} while (input);
	

}
int main()
{
          
   
	test();
	return 0;
}

game.c文件代码实现

#include "game.h"
//初始化棋盘
void init_board(char arr[ROWS][COLS], int rows, int cols, char set)
{
          
   
	int i = 0;
	int j = 0;
	for (i = 0; i < rows; i++)
	{
          
   
		for (j = 0; j < cols; j++)
		{
          
   
			arr[i][j] = set;
		}
	}
}

//打印棋盘
void show_board(char arr[ROWS][COLS], int row, int col)
{
          
   
	int i = 0;
	int j = 0;
	printf("-------扫雷-------
");
	for (i = 0; i <= col; i++)
	{
          
   
		printf("%d ", i);
	}
	printf("
");
	for (i = 1; i <= row; i++)
	{
          
   
		printf("%d ", i);
		for (j = 1; j <= col; j++)
		{
          
   
			
			printf("%c ", arr[i][j]);
		}
		printf("
");
	}
}

//布置雷
void set_mine(char mine[ROWS][COLS], int row, int col)
{
          
   
	int count = EASY_COUNT;
	int x = 0;
	int y = 0;
	while (count)
	{
          
   
		x = rand() % row + 1;
		y = rand() % col + 1;
		if (mine[x][y] == 0)
		{
          
   
			mine[x][y] = 1;
			count--;
		}
	}
}

int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
          
   
	return mine[x - 1][y - 1] + mine[x - 1][y] + mine[x - 1][y + 1]
		+ mine[x][y - 1] + mine[x][y + 1] + mine[x + 1][y - 1]
		+ mine[x + 1][y] + mine[x + 1][y + 1] - 0 * 8;
}

//排查雷
void find_mine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
          
   
	int x = 0;
	int y = 0;
	int win = 0;
	while (win < row*col - EASY_COUNT)
	{
          
   
		printf("请输入要排查的区域:>
");
		scanf("%d %d", &x, &y);
		if (x >= 1 && x <= row && y >= 1 && y <= col)
		{
          
   
			if (mine[x][y] == 1)
			{
          
   
				printf("抱歉,你被炸死了
");
				show_board(mine, ROW, COL);
				break;
			}
			else
			{
          
   
				int count = get_mine_count(mine, x, y);
				show[x][y] = count + 0;
				show_board(show, ROW, COL);
				win++;
			}
		}
		else
		{
          
   
			printf("坐标非法,请重新输入:>
");
		}
	}
	if (win = row * col - EASY_COUNT)
	{
          
   
		printf("恭喜你,排雷成功
");
		show_board(mine, ROW, COL);
	}
}

game.h文件代码实现

#define ROW 9
#define COL 9

#define ROWS ROW+2
#define COLS COL+2

#define EASY_COUNT 10

#include<stdio.h>
#include<stdlib.h>
#include<time.h>

//初始化棋盘
void init_board(char arr[ROWS][COLS], int rows, int cols, char set);
//打印棋盘
void show_board(char arr[ROWS][COLS],int row,int col);
//布置雷
void set_mine(char mine[ROWS][COLS],int row, int col);
//排查雷
void find_mine(char mine[ROWS][COLS],char show[ROWS][COLS],int row,int col);

总结

本文采用更简单的方式为读者带来扫雷详细代码,读者要想查看详细逻辑,请点连接查看上篇博文。 读者要是觉得看完本文有所帮助,请给博主一点支持。感谢各位读者支持!

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