Java8Lambda表达式实现List转Map
import java.util.ArrayList; import java.util.List; import java.util.Map; import java.util.stream.Collectors; public class LambdaTest { static class Person { private Integer id; private String name; public Person(Integer id, String name) { this.id = id; this.name = name; } public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } public String getName() { return name; } public void setName(String name) { this.name = name; } @Override public String toString() { return "Person{" + "id=" + id + ", name=" + name + + }; } } public static void main(String[] args) { List<Person> people = new ArrayList<>(); people.add(new Person(1, "张三")); people.add(new Person(2, "李四")); people.add(new Person(3, "王五")); //1.遍历输出 people.stream().forEach(p -> { System.out.println(p.toString()); }); //2.取对象的两个属性,变成Map Map<Integer, String> map1 = people.stream().collect(Collectors.toMap(Person::getId, Person::getName)); //Map<Integer, String> map1 = people.stream().collect(Collectors.toMap(Person::getId, Person::getName, (p1, p2) -> p1)); map1.keySet().stream().forEach(k -> { System.out.println("key=" + k + " value=" + map1.get(k)); }); //3.剥离出主键,变成Map //Map<Integer, Person> map2 = people.stream().collect(Collectors.toMap(Person::getId, p -> p)); Map<Integer, Person> map2 = people.stream().collect(Collectors.toMap(Person::getId, p -> p, (p1, p2) -> p2)); //如果这里的key可能存在重复,增添(p1, p2) -> p1,表示如果重复选前者;同理,(p1, p2) -> p2,表示如果重复选后者 map2.keySet().stream().forEach(k -> { System.out.println("key=" + k + " value=" + map2.get(k)); }); } }
打印结果: Person{id=1, name=‘张三’} Person{id=2, name=‘李四’} Person{id=3, name=‘王五’} key=1 value=张三 key=2 value=李四 key=3 value=王五 key=1 value=Person{id=1, name=‘张三’} key=2 value=Person{id=2, name=‘李四’} key=3 value=Person{id=3, name=‘王五’}
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