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C++ vector容器遍历并删除元素

在使用C++ vector的迭代器遍历并删除元素时,存在一些不注意的误区,这里特此记录。

在使用迭代器遍历vector元素时,错误的删除方法:

vector<int>::iterator it = vec.begin();
  for (; it != vec.end();) {
    vector<int>::iterator tmpit = it;
    it++;
    vec.erase(tmpit);
  }

正确的删除方法:

vector<int>::iterator it = vec.begin();
  for (; it != vec.end();) {
    it = vec.erase(it);
  }

一个例子:

vector<int> vec;
  for (int i = 0; i < 20; ++i) {
    vec.push_back(i + 1);
  }
  for (int i = 0; i < vec.size(); ++i) {
    cout << vec[i] << " ";
  }
  cout << endl;

  vector<int>::iterator it = vec.begin();
  for (; it != vec.end();) {
    cout << (*it) << endl;
    if ((*it) % 2 == 1) {
      vector<int>::iterator tmp = it;
      it = vec.erase(tmp);
    } else {
      it++;
    }
  }

  for (int i = 0; i < vec.size(); ++i) {
    cout << vec[i] << " ";
  }
  cout << endl;

输出结果为:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
1 3 5 7 9 11 13 15 17 19

符合预期!

当使用以上错误的删除方式时,

vector<int> vec;
  for (int i = 0; i < 20; ++i) {
    vec.push_back(i + 1);
  }
  for (int i = 0; i < vec.size(); ++i) {
    cout << vec[i] << " ";
  }
  cout << endl;

  vector<int>::iterator it = vec.begin();
  for (; it != vec.end();) {
    cout << (*it) << endl;
    if ((*it) % 2 == 0) {
      vector<int>::iterator tmp = it;
      it++;
      vec.erase(tmp);
    } else {
      it++;
    }
  }

  for (int i = 0; i < vec.size(); ++i) {
    cout << vec[i] << " ";
  }
  cout << endl;

输出结果为:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 
1
2
4
6
8
10
12
14
16
18
20
20
Segmentation fault

可以看出,迭代器it的访问已经错乱了。

需要说明的是,vector错误的遍历删除方式,在map中是正确的写法!

重要:vector的erase函数会使迭代器失效,因此,在遍历时使用erase函数后,旧的迭代器就不能再使用了!

看下面一个例子:

vector<int> vec;

  vec.push_back(1);
  vec.push_back(2);

  vector<int>::iterator it = vec.begin();
  for (; it != vec.end();) {
    cout << (*it) << endl;
    if ((*it) % 2 == 1) {
      vector<int>::iterator tmp = it;

      cout << "before erase:" << (*tmp) << endl;

      it = vec.erase(tmp);

      cout << "after erase:" << (*tmp) << endl;

    } else {
      it++;
    }
  }

输出结果为:

1
before erase:1
after erase:2
2

可以看到,erase前的tmp跟it一样,erase之后,tmp并不是旧的it值。

所以万不可在erase之后去访问旧的迭代器!

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