Spring快速入门代码实现
1.利用IDAE创建一个项目ZSpring.
2.配置pom.xml文件,导入spring坐标。
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.lingnan</groupId>
<artifactId>ZSpring</artifactId>
<version>1.0-SNAPSHOT</version>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>5.0.5.RELEASE</version>
</dependency>
</dependencies>
</project>
3.创建项目包com.lingnan.dao并在其下面创建UserDao接口
package com.lingnan.dao;
public interface UserDao {
public void save();
}
4.在com.lingnan.dao.impl下创建一个UserDaoImpl类
package com.lingnan.dao.impl;
import com.lingnan.dao.UserDao;
public class UserDaoImpl implements UserDao {
public void save() {
System.out.println("save running....");
}
}
5.在ZSpringsrcmain esources 新建new一个Spring Config。文件名为applicationContext(名字随意取)并配置其内容,id可以自己取,这里我取userDao,class为UserDaoImpl类的路劲。
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
<bean id="userDao" class="com.lingnan.dao.impl.UserDaoImpl"></bean>
</beans>
6.new一个新的包com.lingnan.demo,创建一个demo类测试。
package com.lingnan.demo;
import com.lingnan.dao.UserDao;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class UserDaoDemo {
public static void main(String[] args) {
ApplicationContext app = new ClassPathXmlApplicationContext("applicationContext.xml");
UserDao userDao = (UserDao) app.getBean("userDao");
userDao.save();
}
}
7.测试结果
8.总结Spring开发步骤
