kotlin键值对数组_Kotlin程序以升序对数组进行排序

kotlin键值对数组

Given an array, we have to sort its elements in ascending order.

给定一个数组，我们必须按升序对其元素进行排序。

Example:

例：

Input:
    arr = [10, 20, 5, 2, 30]

    Output:
    sorted array (Ascending Order): [2, 5, 10, 20, 30]

在Kotlin中以升序对数组进行排序的程序 (Program to sort an array in ascending order in Kotlin)

package com.includehelp.basic

import java.util.*

//Main Function entry Point of Program
fun main(args: Array<String>) {
    //Input Stream
    val s = Scanner(System.`in`)

    //Input Array Size
    print("Enter number of elements in the array: ")
    val size = s.nextInt()

    //Create Integer array of Given size
    val intArray = IntArray(size)

    //Input array elements
    println("Enter Arrays Elements:")
    for (i in intArray.indices) {
        print("intArray[$i] : ")
        intArray[i] = s.nextInt()
    }

    //to Perform Ascending Order Sorting on integer Array
    var temp:Int
    for (i in intArray.indices) {
        for (j in i + 1 until intArray.size) {
            if (intArray[i] > intArray[j]) {
                temp = intArray[i]
                intArray[i] = intArray[j]
                intArray[j] = temp
            }
        }
    }

    //Alternatively we can also use sort() method of Arrays 
    //Class in kotlin to sort in Ascending Order
    //intArray.sort()

    print("Ascending Order: ")
    for (item in intArray) {
        print("$item ")
    }
}

Output

输出量

Enter number of elements in the array: 6
Enter Arrays Elements:
intArray[0] : 5
intArray[1] : 23
intArray[2] : 1
intArray[3] : 0
intArray[4] : 9
intArray[5] : 76
Ascending Order: 0 1 5 9 23 76
----------------
Enter number of elements in the array: 8
Enter Arrays Elements:
intArray[0] : 45
intArray[1] : 3
intArray[2] : 89
intArray[3] : -8
intArray[4] : -45
intArray[5] : 0
intArray[6] : 432
intArray[7] : 6
Ascending Order: -45 -8 0 3 6 45 89 432

翻译自:

kotlin键值对数组