原因

com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field “xxx fieldName” 导致原因是因为Jackson将JSON转换成Java对象时，JSON中包含Java对象没有的属性。

解决方案：

方案一：单个类配置

在类上增加@JsonIgnoreProperties(ignoreUnknown = true)注解

@JsonIgnoreProperties(ignoreUnknown = true)
public class Person {
          
   
    private String name;
    private Integer age;
}

public class Main {
          
   

    private final static ObjectMapper objectMapper = new ObjectMapper();

    public static void main(String[] args) throws JsonProcessingException {
          
   
        String jsonStr = "{"name":"brian7788","age":18,"sex":"1"}";
        Person person = objectMapper.readValue(jsonStr, Person.class);
        System.out.println(person);
    }
}

方案二：全局配置

使用 objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false); 实现全局禁用遇到未知属性抛出异常。

public class Main {
          
   

    private final static ObjectMapper objectMapper = new ObjectMapper();

    // Jackson个性化配置可在静态代码块中完成
    static {
          
   
        // 禁用遇到未知属性抛出异常
        objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
    }
    
	public static void main(String[] args) throws JsonProcessingException {
          
   
	    String jsonStr = "{"name":"brian7788","age":18,"sex":"1"}";
	    Person person = objectMapper.readValue(jsonStr, Person.class);
	    System.out.println(person);
	}
}

方案三：使用@JsonAnySetter注解将JSON中多余的属性反序列化到Java POJO

该方式需要在Java POJO 中增加一个Map的属性用来接收JSON中所有多余的属性，且对应的setter方法入参为key-value键值对。 使用@JsonAnySetter注解可以将JSON中多余出来的属性反序列化到person对象的other属性中去。 使用@JsonAnyGetter 注解将Person对象的other属性中的kay-value键值对以平级的方式序列化到JSON对象当中，注意是和其他属性是平级的。

public class Person {
          
   

    private String name;
    private Integer age;
    private Map<String, Object> other = new HashMap<>();

    public String getName() {
          
   
        return name;
    }

    public void setName(String name) {
          
   
        this.name = name;
    }

    public Integer getAge() {
          
   
        return age;
    }

    public void setAge(Integer age) {
          
   
        this.age = age;
    }

    @JsonAnyGetter
    public Map<String, Object> getOther() {
          
   
        return other;
    }

    @JsonAnySetter
    public void setOther(String key, Object value) {
          
   
        this.other.put(key, value);
    }
}

public class Main {
          
   

    private final static ObjectMapper objectMapper = new ObjectMapper();

    public static void main(String[] args) throws JsonProcessingException {
          
   
        String jsonStr = "{"name":"brian7788","age":18,"sex":"1"}";
        Person person = objectMapper.readValue(jsonStr, Person.class);
        System.out.println(person);
        System.out.println(mapper.writeValueAsString(person));
    }
}