python练习-字符串加密解密

题目描述

输入两行字符串,第一行为需要加密的字符串,第二行为需要解密的字符串,按照加密解密规则输出两行,第一行为加密后的字符串,第二行为解密后的字符串。加密规则:将大写字母变换为该字母后一位字母、并小写输出,将小写字母变换为该字母后一位字母、并大写输出,将数字加1输出(9变换为0),其余字符不变。解密规则对应加密规则的逆过程。

解题思路

跟一样

python代码实现

import re

alphaList = [a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z]

def Encrypt(aucPassword, aucResult=[]):
    for x in aucPassword:
        if re.match([A-Z], x):
            xLower = x.lower()
            idx = alphaList.index(xLower) + 1
            if idx == len(alphaList):
                idx = 0
            x = alphaList[idx]
        elif re.match([a-z], x):
            idx = alphaList.index(x) + 1
            if idx == len(alphaList):
                idx = 0
            x = alphaList[idx].upper()
        elif re.match([0-9], x):
            if x == 9:
                x = 0
            else:
                x = str(int(x) + 1)
        aucResult.append(x)
    print("".join(aucResult))

def unEncrypt(password, result=[]):
    for x in password:
        if re.match([A-Z], x):
            xLower = x.lower()
            idx = alphaList.index(xLower) - 1
            if idx == -1:
                idx = len(alphaList)
            x = alphaList[idx]
        elif re.match([a-z], x):
            idx = alphaList.index(x) - 1
            if idx == -1:
                idx = len(alphaList)
            x = alphaList[idx].upper()
        elif re.match([0-9], x):
            if x == 0:
                x = 9
            else:
                x = str(int(x) - 1)
        result.append(x)
    print(.join(result))

pwdList = []
for i in range(2):
    pwdList.append(input())
Encrypt(pwdList[0])
unEncrypt(pwdList[1])
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