Spring Data JPA - 如何创建查询(3)函数名关键词列表

陈喆,现就职于中科院某研究所担任副研究员,专注于工业云平台、MES系统的设计与研发。

基于函数名创建查询:

public interface UserRepository extends Repository<User, Long> {

  List<User> findByEmailAddressAndLastname(String emailAddress, String lastname);
}

上例的函数将会翻译成查询语句:select u from User u where u.emailAddress = ?1 and u.lastname = ?2

下表列出了JPA支持的关键字和对应的转换语句:

Keyword Sample JPQL snippet And findByLastnameAndFirstname … where x.lastname = ?1 and x.firstname = ?2 Or findByLastnameOrFirstname … where x.lastname = ?1 or x.firstname = ?2 Is,Equals findByFirstname,findByFirstnameIs,findByFirstnameEquals … where x.firstname = ?1 Between findByStartDateBetween … where x.startDate between ?1 and ?2 LessThan findByAgeLessThan … where x.age < ?1 LessThanEqual findByAgeLessThanEqual … where x.age <= ?1 GreaterThan findByAgeGreaterThan … where x.age > ?1 GreaterThanEqual findByAgeGreaterThanEqual … where x.age >= ?1 After findByStartDateAfter … where x.startDate > ?1 Before findByStartDateBefore … where x.startDate < ?1 IsNull findByAgeIsNull … where x.age is null IsNotNull,NotNull findByAge(Is)NotNull … where x.age not null Like findByFirstnameLike … where x.firstname like ?1 NotLike findByFirstnameNotLike … where x.firstname not like ?1 StartingWith findByFirstnameStartingWith … where x.firstname like ?1 (parameter bound with appended %) EndingWith findByFirstnameEndingWith … where x.firstname like ?1 (parameter bound with prepended %) Containing findByFirstnameContaining … where x.firstname like ?1 (parameter bound wrapped in %) OrderBy findByAgeOrderByLastnameDesc … where x.age = ?1 order by x.lastname desc Not findByLastnameNot … where x.lastname <> ?1 In findByAgeIn(Collection<Age> ages) … where x.age in ?1 NotIn findByAgeNotIn(Collection<Age> ages) … where x.age not in ?1 True findByActiveTrue() … where x.active = true False findByActiveFalse() … where x.active = false IgnoreCase findByFirstnameIgnoreCase … where UPPER(x.firstame) = UPPER(?1)

In和NotIn可以使用任何Collection的子类作为参数。

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