ValueError: too many values to unpack (expected 2)
class Mymeta(type):
def __new__(cls, class_name, class_bases, class_attrs):
print(--->, cls) # ---> <class __main__.Mymeta>
print(--->, class_name) # ---> Chinese
print(--->, class_bases) # ---> (<class object>,)
print(--->, class_attrs) # Chinese, country: china, skin: yello, __init__: ....
print(class_attrs.items())
update_attrs = {}
for key, value in class_attrs:
if not callable(value) and not key.startswith(__):
update_attrs[key.upper()] = value
else:
update_attrs[key] = value
return type.__new__(cls, class_name, class_bases, update_attrs)
class Chinese(object, metaclass=Mymeta):
country = china
skin = yello class Mymeta(type): def __new__(cls, class_name, class_bases, class_attrs): print(--->, cls) # --->
返回了下面的错误:
for key, value in class_attrs: ValueError: too many values to unpack (expected 2)for key, value in class_attrs: ValueError: too many values to unpack (expected 2)
原因是字典这个是一个迭代器对象,参考官方文档找到下列说明,字典只支持Key的遍历,,如果想对key,value,则可以使用items方法。 The “implicit” iteration that dictionaries support only iterates over keys.
python只支持对于key的遍历,所以不能使用for k,v这种形式,这个时候会提示ValueError: too many values to unpack, 正确代码如下:
for key, value in class_attrs.items():for key, value in class_attrs.items():
