【python】暴力破解压缩包密码

import zipfile
import itertools
 
dictionaries = [1, 2, 3, 4,5,6,7,8,9,0,
a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z,
A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z,
.,,,:,?,<,>,
 ] #组成破解字典的关键字符（可以按照自己需求添加）
 
def allkeyword(number): #排列出字符所有number个字符的组合
 allkey1 = itertools.product(dictionaries,repeat=number)
 allkey2 = (.join(i) for i in allkey1)
 return allkey2
 
def trypassword (fileName,password):#用trypassword函数返回的True或者Flase来判定程序是否终止。
 try:
  ZIPFILE = zipfile.ZipFile(fileName) #定义对象，相当于定义一个压缩文件1.zip
  ZIPFILE.extractall(path=r./,pwd=password.encode(utf-8))
  print(f"解压成功,正确密码为：{
            
     password}")
  return True
 except:
  #print(f"解压失败,尝试密码为：{password}")
  return False
 
def start(fileName):
 import math
 for number in range(20):#遍历长度在20以内的所有可能密码组合
  print("密码长度：",number+1)
  index=0
  for pwd in allkeyword(number+1) :
   index=index+1
   print("进度:",str( round(100*index/(len(dictionaries)**(number+1)),2) )+"%",end="
")
   if trypassword(fileName,pwd):#判断结果是否正确
    print()
    return
  print()
start("test.zip")

参考：http://www.cppcns.com/jiaoben/python/381295.html